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Question:

From the top of a 64-metres high tower, a stone is thrown upwards vertically with a velocity of 48 m/s. The greatest height (in metres) attained by the stone, assuming the value of gravitational acceleration g=32 m/s², is

128

100

112

88

Solution:

u=48 m/s, a=-32 m/s²
At the highest point, v=0
Since, v² - u² = 2as, ⇒ |s| = √(0² - 48²)/(2 x -32) m ⇒ |s| = 36m
So, total height attained by the stone from the ground = 36 + 64 = 100m