Eduprobe
Question:
Fusion of MnO2 with KOH in presence of O2 produces a salt W. Alkaline solution of W upon electrolytic oxidation yields another salt X. The manganese containing ions present in W and X, respectively are Y and Z. Correct statement(s) is (are) A) In both Y and Z, α−bonding occurs between p−orbitals of oxygen and d-orbitals of manganese B) Both Y and Z are coloured and have tetrahedral shape C) In aqueous acidic solution, Y undergoes disproportionation reaction to give Z and MnO2 D) Y is diamagnetic in nature while Z is paramagnetic
In both Y and Z, α−bonding occurs between p−orbitals of oxygen and d-orbitals of manganese
Both Y and Z are coloured and have tetrahedral shape
In aqueous acidic solution, Y undergoes disproportionation reaction to give Z and MnO2
Y is diamagnetic in nature while Z is paramagnetic
Solution:
Correct option is D. Y is diamagnetic in nature while Z is paramagnetic.
The fusion of MnO2 with KOH in the presence of O2 produces potassium manganate(VI), K2MnO4 (W). The manganate(VI) ion, MnO42−, has Y as the manganese containing ion.
Electrolytic oxidation of K2MnO4 in alkaline solution produces potassium permanganate, KMnO4 (X). The permanganate ion, MnO4−, has Z as the manganese containing ion.
In MnO42− (Y), Mn is in +6 oxidation state and has 1 unpaired electron which makes it paramagnetic.
In MnO4− (Z), Mn is in +7 oxidation state and has 0 unpaired electrons which makes it diamagnetic.
Therefore, statement D is correct: Y is paramagnetic while Z is diamagnetic.