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Question:

Given that, E^0_O_2 / H_2O = +1.23V, E^0_S_2O_8^2- / SO_4^2- = +2.05V, E^0_Br_2 / Br^- = +1.09V, and E^0_Au^3+ / Au = +1.4V, the strongest oxidizing agent is:?

O_2

S_2O_8^2-

Br_2

Au^3+

Solution:

Correct option is B. S_2O_8^2-. The strongest oxidizing agent is the one with the highest standard reduction potential, which is S_2O_8^2- / SO_4^2-.