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Question:

Given VCM=2 m/s, m=2 kg, R=4 m. Find angular momentum of ring about origin if it is in pure rolling.

32 kgm2/

24 kgm2/

16 kgm2/

8 kgm2/

Solution:

Correct option is A. 32 kgm2/
We know that
Angular momentum of a body about any point, L→=ICM.ω+mVCMr
Angular velocity , ω=v/R=2/4=0.5 rad/sec
ICM=mR2
So, L→=mR2.ω+mVCM.
=2×16×0.5+2×2×4=16+16
L→=32kg×m2/s=32kgm2/.