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Question:

Given: Co³⁺ + e⁻ → Co²⁺; E⁰ = +1.81 V
Pb⁴⁺ + 2e⁻ → Pb²⁺; E⁰ = +1.67 V
Ce⁴⁺ + e⁻ → Ce³⁺; E⁰ = +1.61 V
Bi³⁺ + 3e⁻ → Bi; E⁰ = +0.20 V
Oxidizing power of the species will increase in the order :

Ce⁴⁺ < Pb⁴⁺ < Bi³⁺ < Co³⁺

Co³⁺ < Pb⁴⁺ < Ce⁴⁺ < Bi³⁺

Co³⁺ < Ce⁴⁺ < Bi³⁺ < Pb⁴⁺

Bi³⁺ < Ce⁴⁺ < Pb⁴⁺ < Co³⁺

Solution:

The correct option is D Bi³⁺ < Ce⁴⁺ < Pb⁴⁺ < Co³⁺
As the reduction potential (E⁰red) increases, oxidizing power also increases. So, the correct order is: Bi³⁺ < Ce⁴⁺ < Pb⁴⁺ < Co³⁺.