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Question:

Given, E°Cr³⁺/Cr = -0.74V; E°MnO₄⁻/Mn²⁺ = 1.51V; E°Cr₂O₇²⁻/Cr³⁺ = 1.33V; E°Cl/Cl⁻ = 1.36V. Based on the data given above, the strongest oxidizing agent will be: Cr³⁺, Mn²⁺, MnO₄⁻, Cl⁻

Cl⁻

Cr³⁺

Mn²⁺

MnO₄⁻

Solution:

The strongest oxidizing agent is the one with the highest standard reduction potential (E°). From the given data:

E°Cr³⁺/Cr = -0.74V
E°MnO₄⁻/Mn²⁺ = 1.51V
E°Cr₂O₇²⁻/Cr³⁺ = 1.33V
E°Cl/Cl⁻ = 1.36V

Comparing the reduction potentials, MnO₄⁻ has the highest positive value (1.51V). Therefore, MnO₄⁻ is the strongest oxidizing agent among the given options.