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Question:

Half mole of an ideal monoatomic gas is heated at constant pressure of 1 atm from 20°C to 90°C. Work done by gas close to: (Gas constant R = 8.31 J/mol.K)

146 J

73 J

581 J

291 J

Solution:

Work Done = PΔV = nRΔT = 1 × 8.31 × (90 - 20) = 581 J