How many electrons flow through a metallic wire if a current of 0.5 A is passed for 2 hours?

Charge passed: q = it = 0.5 × 2 × 60 × 60 = 3600 C
Number of Faraday passed: F = 3600/96500
Number of electrons passed: Ne = (3600/96500) × 6.022 × 10^23 = 2.24 × 10^22 electrons