Eduprobe
Question:
How many structures of X is possible?
5
6
4
3
Solution:
Possible products: cis and trans CH3−CH=CH−CH3, and CH3−CH2−CH=CH2. Total products = 3
5
6
4
3
Possible products: cis and trans CH3−CH=CH−CH3, and CH3−CH2−CH=CH2. Total products = 3