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Question:

A boxB1contains1white ball,3red balls and2black balls. Another boxB2contains2white balls,3red balls and4black balls. A third boxB3contains3white balls,4red balls and5black balls.If 1 ball is drawn from each of the boxesB1,B2andB3, the probability that all 3 drawn balls are of the same colour is8264855864890648566648A boxB1contains1white ball,3red balls and2black balls. Another boxB2contains2white balls,3red balls and4black balls. A third boxB3contains3white balls,4red balls and5black balls.If 1 ball is drawn from each of the boxesB1,B2andB3, the probability that all 3 drawn balls are of the same colour is8264855864890648566648A boxB1contains1white ball,3red balls and2black balls. Another boxB2contains2white balls,3red balls and4black balls. A third boxB3contains3white balls,4red balls and5black balls.B1B1B1B1BBB11111111113333322222B2B2B2B2BBB22222222223333344444B3B3B3B3BBB33333333334444455555B1,B2B1,B2B1,B2B1BBB11111,,B2BBB22222B3B3B3B3BBB3333382648826488264882648826488264882648826488282826486486485586485586485586485586485586485586485586485586485585585586486486489064890648906489064890648906489064890648909090648648648566648566648566648566648566648566648566648566648566566566648648648A906489064890648906489064890648906489064890648909090648648648B566648566648566648566648566648566648566648566648566648566566566648648648C826488264882648826488264882648826488264882648828282648648648D558648558648558648558648558648558648558648558648558648558558558648648648?

90648

566648

82648

558648

Solution:

P(required)=P(all are white)+P(all are red)+P(all are black)