If 100 times the 100th term of an AP with non zero common difference equals the 50 times its 50th term, then the 150th term of this AP is:

Let a be the first term and d be the common difference of the AP.
Given: 100(a+99d) = 50(a+49d) [using nth term an = a + (n-1)d]
⇒ 2a + 198d = a + 49d
⇒ a + 149d = 0
Also, T150 = a + 149d = 0
Hence, the option '0' is correct.