If 1022 gas molecules each of mass 10-26 kg collided with a surface (perpendicular to it) elastically per second over an area 1 m2 with a speed 104 m/s, the pressure exerted by the gas molecules will be of the order of

Correct option is C. 103 N/m
Note: Pressure is defined as normal force per unit area. Force is calculated as change in momentum/ time. By this answer is 2 N/m2. None of the option matches so this question must be Bonus.
Detailed solution is as following.
Magnitude of change in momentum per collision = 2mv
Pressure = Force/Area = N(2mv)/1 = 1022 × 2 × 10-26 × 104 / 1 = 2 N/m2.