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Question:

If 2kg mass is rotating on a circular path of radius 0.8m with angular velocity of 44 rad/sec. If radius of the path becomes 1m then what will be the value of angular velocity?

28.16 rad/sec

8.12 rad/sec

35.26 rad/sec

19.28 rad/sec

Solution:

The correct option is A 28.16 rad/sec
Angular momentum conservation yields: ω₂ = (I₁ω₁)/I₂. I₁/I₂ = r₁²/r₂²
Substituting the values, we get ω₂ = (0.64 × 44) = 28.16 rad/s.