Eduprobe
Question:
If 3x = z, zy = 5, 5z = 3, then xyz = ?
0
5
3
1
Solution:
3x=z⇒xxy=5.. (i)[∵zy=5]and5z=3So,5=31z.. (ii)From equation (1) and (2)3xy=31z(Compare both side)xy=1z⇒xyz=1So, ans(d)is correct
0
5
3
1
3x=z⇒xxy=5.. (i)[∵zy=5]and5z=3So,5=31z.. (ii)From equation (1) and (2)3xy=31z(Compare both side)xy=1z⇒xyz=1So, ans(d)is correct