If (5+2√6)(x²)+ (5-2√6)(x²)=10, then x is equal to

Let (5+2√6)x²=a
We get, (5-2√6)x²=1/a
∴ a + 1/a = 10
→ a² -10a + 1 = 0
→ a = 10 ± √(100-4)/2 = 5 ± 2√6 = (5+2√6)(x²)(assumed)
→ x² = ±1
→ x² = 4 or 2
→ x² = 4 → x = ±2
or x² = 2 → x = ±√2