A³ + I = A(A³ - I)
A³ - I = A(A - I)
A⁴ - I = A² + I
A² + I = A(A² - I)
A = [[0, 1], [1, 0]]
A² = [[0, 1], [1, 0]] [[0, 1], [1, 0]] = [[1, 0], [0, 1]] = I
A³ = A²A = IA = A = [[0, 1], [1, 0]]
A⁴ = A²A² = IA = I = [[1, 0], [0, 1]]
Let's check each option:
A³ + I = A(A³ - I)
A + I = A(A - I)
[[0, 1], [1, 0]] + [[1, 0], [0, 1]] = [[0, 1], [1, 0]]([[0, 1], [1, 0]] - [[1, 0], [0, 1]])
[[1, 1], [1, 1]] = [[0, 1], [1, 0]][[-1, 1], [1, -1]]
[[1, 1], [1, 1]] = [[-1, -1], [-1, -1]] (Incorrect)
A³ - I = A(A - I)
A - I = A(A - I)
[[0, 1], [1, 0]] - [[1, 0], [0, 1]] = [[0, 1], [1, 0]]([[0, 1], [1, 0]] - [[1, 0], [0, 1]])
[[-1, 1], [1, -1]] = [[0, 1], [1, 0]][[-1, 1], [1, -1]]
[[-1, 1], [1, -1]] = [[-1, 1], [1, -1]] (Correct)
A⁴ - I = A² + I
I - I = I + I
[[0, 0], [0, 0]] = [[2, 0], [0, 2]] (Incorrect)
A² + I = A(A² - I)
I + I = A(I - I)
2I = A(0) = [[0, 0], [0, 0]] (Incorrect)
Therefore, the statement A³ + I = A(A³ - I) is not correct.