If A is a 3x3 matrix such that |5.adjA|=5, then |A| is equal to

Given, |5adjA|=5
We know that |kA| = kⁿ|A|, where n is the order of the matrix A.
Also, |adjA| = |A|ⁿ⁻¹
Here, n=3
Therefore, |5adjA| = 5³|adjA| = 125|adjA|
Since |adjA| = |A|²
|5adjA| = 125|A|² = 5
|A|² = 5/125 = 1/25
|A| = ±√(1/25) = ±1/5
|A| = ±0.2
However, none of the options match this value. Let's re-examine the given information.
Given |5adjA| = 5
|5adjA| = 5³|adjA| = 125|adjA| = 5
|adjA| = 5/125 = 1/25
Since |adjA| = |A|ⁿ⁻¹ = |A|² for a 3x3 matrix,
|A|² = 1/25
|A| = ±1/5
Let's check the options:
Option A: ±1
Option B: ±15
Option C: ±125
Option D: ±5
None of the options match the calculated value of |A| = ±1/5. There might be an error in the problem statement or the provided options.