If A = {(x, y): x² + y² ≤ 1; x, y ∈ R} and B = {(x, y): x² + y² ≥ 4; x, y ∈ R}, then A - B = φ, B - A = φ, A ∩ B ≠ φ, A ∩ B = φ
A - B = φ
A ∩ B ≠ φ
B - A = φ
A ∩ B = φ
Solution:
A is the set of all points on or inside the inner circle x² + y² = 1. B is the set of all points on or outside the outer circle x² + y² = 4. ∴ A - B = A, B - A = B, A ∩ B = φ.