If a tangent to a suitable conic (Column I) is found to be y=x+8 and its point of contact is (8,16), then which of the following options is the only CORRECT combination?

Point of contact :(8,16) Equation of tangent ⇒y=x+8 ⇔Slope(m)=1. i.e. Matching with (i) of column 2 my=m²x+a y=x+8 Hence, m=1 and a=8 Matching with (P) of column 3 :(am²,2am) ⇒(8(1)²,2×8(1))=(8,16) Matching with column 1 1) x²+y²-a²=0 ⇒8²+16²-a²≠0 2) x²+a²y²-a²=0 ⇒8²+(8²×16²)-a²≠0 3) y²=4ax ⇒16²=4(8)(8)=0 Hence, equation of curve ⇒y²=4ax Point of contact :(am²,2am) Tangent ⇒my=m²x+a Hence, option B is correct.