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Question:

If a is the length of the side of a cube, the distance between the body-centered atom and one corner atom in the cube will be:

2√3a

√34a

4√3a

√32a

Solution:

We know that for bcc structure, r=√3/4a
Hence, 2r=√3/2a
2r represents the distance between the body-centered atom and one corner atom.
Thus, if a represents the length of the side of a cube, the distance between the body-centered atom and one corner atom in the cube will be √32a.