5π12
5π6
2π3
π4
Correct option is C. 2π3cos²α + cos²β + cos²γ = 11/2 + 1/4 + cos²γ = 1cos²γ = 1 - 3/4 = 1/4cos γ = ±1/2⇒ γ = π/3 or 2π/3