If AD and PM are medians of triangles ABC and PQR respectively where △ABC≅△PQR, prove that AB/PQ = AD/PM.

Since, △ABC≅△PQR ⇒ AB/PQ = BC/QR = AC/PR ∠A = ∠P, ∠B = ∠Q, ∠C = ∠R
But, BC = 2BD and QR = 2QM
Hence, AB/PQ = BD/QM = AC/PR
In △ABD and △PQM,
AB/PQ = BD/QM and ∠B = ∠Q
By SAS similarity, △ABD≅△PQM,
∴ AB/PQ = AD/PM
Hence Proved