9
21
24
Given,∣∣∣∣∣x2+xx+1x2x2+3xx3xx2+2x+32xx∣∣∣∣∣=axR1⟶R1+R3∣∣∣∣∣2x2+3x+33x3xx2+3xx3xx2+2x+32xx∣∣∣∣∣=axR1⟶R1−R2∣∣∣∣∣4002x2+3xx3xx2+2x+32xx∣∣∣∣∣=ax⇒4[6x2xx2+6x+3x]=ax⇒24x=axOn comparing, we geta=24