Eduprobe
Question:
If bromine atom is available in the form of two isotopes ⁷⁹₃₅Br and ⁸¹₃₅Br
Solution:
Average atomic mass of bromine atom = (79 × 49.7)/100 + (81 × 50.3)/100 = 39.273 + 40.743 = 80.016
Average atomic mass of bromine atom = (79 × 49.7)/100 + (81 × 50.3)/100 = 39.273 + 40.743 = 80.016