devarshi-dt-logo

Question:

If f0=5 cm, λ=600A0, a=1 cm for a microscope, then what will be its resolving power?

10.9×10⁵/m

11.9×10⁵/m

10.9×10⁴/m

10.9×10³/m

Solution:

Correct option is B. 10.9×10⁵/m
R.P.=2μsinθ
1.22λ
μ=1
tanθ≈sinθ=a/f=1/5=0.2
⇒R.D.=2×1×0.2/(1.22×6×10⁻⁷)=4×10⁶/3.66
RP.=10.9×10⁵/m.