Eduprobe
Question:
If f:R→R is a differentiable function and f(2)=6, then limx→2∫2xf(t)dt/(x−2) is:
2f(2)
24f'(2)
0
12f'(2)
Solution:
limx→2∫2xf(t)dt/(x−2)
L Hospital Rule
limx→22f(x)f'(x)/1 = 2f(2) = 12f'(2)
2f(2)
24f'(2)
0
12f'(2)
limx→2∫2xf(t)dt/(x−2)
L Hospital Rule
limx→22f(x)f'(x)/1 = 2f(2) = 12f'(2)