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Question:

If m and e are the mass and charge of the revolving electron in the orbit of radius r for hydrogen atom, the total energy of the revolving electron will be:

12ke2r

−ke2r

mke2r

󔼔ke2r

Solution:

Total energy=K.E.+P.E.
K.E.=½mv²=12ke2r (cenrtipetal force)
P.E. = −ke2r
T.E.=12ke2r+−ke2r=−12ke2r
Hence, option B is correct.