If maximum speed of a particle in SHM is given by Vm. What is its average speed?
πVm2
2Vmπ
πVm4
Vm√2
Solution:
Let the SHM be represented as x = A sin(ωt + φ) Thus the speed of a particle = dx/dt = |Aωcos(ωt + φ)| ⇒ Vm = Aω The average speed of the particle = ∫₀^(2π/ω)|Aωcos(ωt + φ)| dt / (2π/ω) = 2Aω/π = 2Vm/π