1√n=1√n1+1√n2+1√n3
n=n1+n2+n3
1/n=1/n1+1/n2+1/n3
√n=√n1+√n2+√n3
n1=1/(2l1)√(T/μ)n2=1/(2l2)√(T/μ)n3=1/(2l3)√(T/μ)n=1/(2l)√(T/μ)l=l1+l2+l31/n=1/n1+1/n2+1/n3