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Question:

If sin(sin⁻¹(1/5) + cos⁻¹x) = 1, then find the value of x.

Solution:

sin(sin�+cos𕒵x)=1sin(sin�+cos𕒵x)=sinπ2∴sin�+cos𕒵x=π2Letsin�=θ, sosinθ=15.. (1)∴θ+cos𕒵x=π2cos𕒵x=π2−θx=cos(π2−θ)x=sinθ=15...from (1)