If S_n the sum of first n terms of an AP is given by S_n = 3n^2 - 4n, find the n^th term.

Given Sum of n terms is S_n=3n^2-4n
So Sum of n-1 terms is S_n-1=3(n-1)^2-4(n-1)=3n^2-6n+3-4n+4=3n^2-10n+7
Sum of n terms is equal to sum of n-1 terms plus n^th term
n^th term =S_n-S_n-1=3n^2-4n-(3n^2-10n+7)
n^th term=6n-7