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Question:

If solubility product of Zr_3(PO_4)_4 is denoted by K_sp and its molar solubility is denoted by S, then which of the following relation between S and K_sp is correct?

S=(Ksp929)1/9

S=(Ksp216)1/7

S=(Ksp6912)1/7

S=(Ksp144)1/6

Solution:

Correct option is D. S=(Ksp6912)1/7
Solution:- (D) S=(Ksp6912)1/7
Zr3(PO4)4(s)⇌3Zr4+(aq)+4PO43−(aq)
Ksp=[Zr4+]3[PO43−]4=(3S)3 (4S)4=6912S7
∴S=(Ksp6912)1/7