6
83
103
-2;3
Correct option is C. 6(x,y): y² ≤ 4x, x + y ≤ 1, x ≥ 0, y ≥ 0A = ∫₀^(3-√2)/2 √(4x) dx + 1/2(1 - (3 - √2)/2)(1 - (3 - √2)/2) = 2[x³/²]₀^((3-√2)/2) / (3/2) + 1/2((√2 - 1)/2)((√2 - 1)/2) = 8/3√2 + (-1/3)a = 8/3, b = -1/3a - b = 6.