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Question:

If the de-Broglie wavelength of a particle of mass m is 100 times its velocity, then its value in terms of its mass (m) and Planck's constant (h) is:

110√amh

10√amh

110√ahm

10√ahm

Solution:

The correct option is B. 10√amh
The de-Broglie wavelength of a particle is given by, λ = h/mv
According to the given question λ = 100v
100v = h/mv
So v² = h/100m
λ = 100v
λ = 10√amh
Hence, the correct option is B.