If the de-Broglie wavelength of a particle of mass m is 100 times its velocity, then its value in terms of its mass (m) and Planck's constant (h) is:
110√amh
10√amh
110√ahm
10√ahm
Solution:
The correct option is B. 10√amh The de-Broglie wavelength of a particle is given by, λ = h/mv According to the given question λ = 100v 100v = h/mv So v² = h/100m λ = 100v λ = 10√amh Hence, the correct option is B.