If the fourth term in binomial expansion of (√(x + log₁₀x) + 1)⁶ is equal to 20000, and x > 1, then the value of x is:

Correct option is D. 10

Given (√(x + log₁₀x) + 1)⁶

General term
T_(r+1) = ⁶Cᵣ(√(x + log₁₀x))⁶⁻ʳ

The fourth term of the expansion is ⁶C₃(√(x + log₁₀x))³ = 20000
(√(x + log₁₀x))³ = 1000
√(x + log₁₀x) = 10
x + log₁₀x = 100 = 10²
x = 10