" />
110
59
56
11!(2!)3
First letter is R and Fourth letter is E.
So now we have 11 letters left with 2E, 2A, 1M, 1D, 1I, 1T, 1R and 2N.
And with this we have to form a two-letter word.
There will be 2 cases when both these two letters of the middle will be the same. And this will be when they both are either EE, AA or NN.
Now when middle two letters are not same. So we have to form a 2 letter word with 8 letters without repetition .
Number of such words will be 8 × 7 = 56
Hence, the total number of such four-letter words with R as the first letter and E as the last letter will be 56 + 3 = 59.