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Question:

If the frustum of a cone has a height of 6 cm and radius of 5 cm and 9 cm respectively; then its cubical volume will be ..............cm³

320π

151π

302π

98π

Solution:

Given h=6 cm, R₁=9 cm and R₂=5 cm
Volume of the frustum of cone = (1/3)πh(R₁² + R₂² + R₁R₂)
volume of the frustum of cone = (1/3) × π × 6 ((9)² + (5)² + (9)(5)) = 302π