If the length of the perpendicular from the point (β, 0, β) (β≠ 0) to the line, x1 = y - 10 = z + 1-1 is √(32), then β is equal to:
-1;
-2;
1
2
Solution:
Correct option is A. -1;One of the point on line is P(0,1,-1) and given point is Q(β,0,β).SO,PQ→=βi^+(-1)j^+ (β+1)k^Hence, β²+1+(β+1)²-(β-β-1)²/2=32 2β²+2β= 2β²+2β=32 β=0,-1 →β=-1(as β≠0)