If the line ax+y=c touches both the curves x²+y²=1 and y²=4√2x, then |c| is equal to:
2
1√2
1/2
√2
Solution:
Tangent to y²=4√2x is y=mx+√2/m This is also tangent to x²+y²=1 ⇒ |√2/m|/√1+m²=1 ⇒ m=±1 Tangent will be y=x+√2 or y=-x-√2 Compare with y=-ax+c ⇒ a=±1; c=±√2 ∴|c|=√2