3√5
√15/2
2√5
√5/2
x²/24 - y²/18 = 1 ⇒ a=√24; b=√18
Parametric normal: √24cosθ⋅x + √18⋅ycotθ = 42
At x=0: y = 42/√18tanθ = 7√3 (from given equation)
⇒ tanθ = √3/2 ⇒ sinθ = ±√3/√5
Slope of parametric normal = -√24cosθ/√18cotθ = m ⇒ m = -√4/3sinθ = -2/√5 or 2√5.