If the magnetic field of a plane electromagnetic wave is given by (The speed of light=3×10⁸ m/s) B=100×10⁻⁶sin[2π×2×10¹⁵(t−xc)], then the maximum electric field associated with it is
4×10⁴N/C
4.5×10⁴N/C
6×10⁴N/C
3×10⁴N/C
Solution:
The correct option is D 3×10⁴N/C E0=B0×c=100×10⁻⁶×3×10⁸=3×10⁴N/C ∴correct answer is 3×10⁴N/C.