Class interval | Frequency |
---|---|
0-10 | 5 |
10-20 | x |
20-30 | 20 |
30-40 | 15 |
40-50 | y |
50-60 | 5 |
Total | 60 |
Given: Median = 28.5 and n = Σfi = 60
We have, n = 60 ⇒ n/2 = 30
Since the median is given to be 28.5, thus the median class is 20-30.
Therefore n/2 = 30, l = 20, f = 20, cf = 5 + x, and h = 10
Substituting these values in the formula
Median = l + ((n/2 - cf)/f) × h
⇒ 28.5 = 20 + ((30 - (5 + x))/20) × 10
⇒ 28.5 = 20 + (25 - x)/2
⇒ 57 = 40 + 25 - x
⇒ x = 8
Also, 45 + x + y = 60
with x = 8, we get y = 7
Hence, (x, y) = (8, 7)