If the point (3,4) lies on the graph of the equation 3y=ax+7, find the value of a.

Given line is 3y=ax+7
Since, the point (3,4) lies on the line 3y=ax+7.
i.e., x=3 and y=4 satisfies the equation.
⇒3y=ax+7
⇒3×4=a×3+7
⇒12=3a+7
⇒3a=12−7
⇒3a=5
⇒a=5/3
Therefore, the value of a is 5/3.