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Question:

If the shortest wavelength in Lyman series of hydrogen atom is A, then the longest wavelength in Paschen series ofHe+is :36A75A936A59A5If the shortest wavelength in Lyman series of hydrogen atom is A, then the longest wavelength in Paschen series ofHe+is :36A75A936A59A5He+He+He+HHe+eee+++36A736A736A736A736A736A736A736A736A36A3636AA7775A95A95A95A95A95A95A95A95A5A55AA99936A536A536A536A536A536A536A536A536A36A3636AA5559A59A59A59A59A59A59A59A59A9A99AA555A36A736A736A736A736A736A736A736A736A736A36A3636AA777B9A59A59A59A59A59A59A59A59A59A9A99AA555C5A95A95A95A95A95A95A95A95A95A5A55AA999D36A536A536A536A536A536A536A536A536A536A36A3636AA555?

36A7

9A5

5A9

36A5

Solution:

For Lyman serieshydrogenatom, the shortest wavelength corresponds to:n1=1andn2=∞1λ=RZ2[1n21−1;n22]1A=R[112−1;∞2]1A=R (1)For Paschen series ofHe+ion, the longest wavelength corresponds to :n1=3andn2=41λ=RZ2[1n21−1;n22]1λ=1A×22×[132−1;42]λ=36A7