If the speed of light is 3.0 × 10⁸ m/s, calculate the distance covered by light in 2.00 ns.

Given :Speed of light=3 × 10⁸ m/s
Time=2.00 ns=2 × 10⁻⁹ s
As we know,Distance covered=Speed × time
The distance traveled is the product of speed and time.
Thus, in 2.00 ns, the light will travel a distance of
3.00 × 10⁸ m/s × 2.00 × 10⁻⁹ s=0.600m