If the tangents on the ellipse 4x^2 + y^2 = 8 at the point (1,2) and (a,b) are perpendicular to each other, then a^2 is equal to?

Correct option is B. 2/17. For ellipse 4x^2 + y^2 = 8 and tangent equation dy/dx = −4x/y = −2 at point (1,2), at the second point (a,b), b = −8a, leading to b^2 = 64a^2. Solving gives a^2 = 2/17.