If the truth value of the statement p→(¬q∨r) is false (F), then the truth values of the statements p, q, r are respectively.

Correct option is C. T, F, T

The implication p → (¬q ∨ r) is false only when p is true and (¬q ∨ r) is false.
(¬q ∨ r) is false only when ¬q is false and r is false. Since ¬q is false, q must be true. Therefore, p is true, q is true, and r is false. The truth values are T, T, F.
However, option C is listed as T, F, T. This seems to be an error in either the question or the provided solution. Let's analyze why C might be considered correct. If we consider the case where p is true, ¬q∨r is false only if both ¬q is false and r is false. If ¬q is false then q is true and if r is false then the truth values of p, q, and r are T, T, F which is not given as an option.
Let's reconsider the statement. p→(¬q∨r) is false only when p is true and (¬q∨r) is false. (¬q∨r) is false if and only if ¬q is false and r is false. If ¬q is false then q is true. If r is false then the truth values are T, T, F. Option B gives this as the answer. Therefore there is an inconsistency between the question and the provided solution. Option B, T, T, F is the correct solution based on the truth table for implication.