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Question:

If x gram of gas is adsorbed by m gram of adsorbent at pressure P, the plot of log(x/m) versus log P is linear. The slope of the plot is: (n and k are constants and n > 1)

n

1/n

logk

2k

Solution:

According to the Freundlich adsorption isotherm, the relationship between the amount of gas adsorbed (x/m) and the pressure (P) is given by:

x/m = kP^(1/n)

where k and n are constants.

Taking the logarithm of both sides, we get:

log(x/m) = log k + (1/n)log P

This equation is of the form y = c + mx, where y = log(x/m), x = log P, c = log k, and m = 1/n.

A plot of log(x/m) versus log P will be a straight line with a slope of 1/n and an intercept of log k.

Therefore, the slope of the plot is 1/n.