If (x² + y²)² = xy, find dy/dx

Now the given equation is (x² + y²)² = xy
Or, (x²)² + 2x²y² + (y²)² = xy → x⁴ + 2x²y² + y⁴ = xy
Differentiating the above expression w.r.t x, we get
4x³ + 4xy² + 4x²y(dy/dx) + 4y³(dy/dx) = y + x(dy/dx)
4x³ + 4xy² + y = x(dy/dx) - 4x²y(dy/dx) - 4y³(dy/dx)
4x³ + 4xy² + y = (x - 4x²y - 4y³)(dy/dx)
dy/dx = (4x³ + 4xy² + y) / (x - 4x²y - 4y³)