Eduprobe
Question:
If y = sec(tan⁻¹x), then dy/dx at x=1 is equal to
12
1
1√2
√2
Solution:
y = sec(tan⁻¹x)
dy/dx = sec(tan⁻¹x)tan(tan⁻¹x) * 1/(1+x²)
dy/dx|x=1 = √2 × 1 × 1/2 = 1/√2.
12
1
1√2
√2
y = sec(tan⁻¹x)
dy/dx = sec(tan⁻¹x)tan(tan⁻¹x) * 1/(1+x²)
dy/dx|x=1 = √2 × 1 × 1/2 = 1/√2.